Question

A magnetic needle suspended in a vertical plane at 30^ from the magnetic meridian makes an angle of 45^with horizontal .Find the true angle of dip

Answer 1

Answer:

The true angle of dip is 40.89°.

Explanation:

Given that,

Vertical angle = 30°

Horizontal angle = 45°

Magnet makes an angle of 30° with magnetic meridian

Horizontal component is

$B_{H}'=B_{H}\cos\theta$

Where, $B_{H}$ = horizontal magnetic field

Put the value into the formula

$B_{H}'=B_{H}\cos30$

$B_{H}=\dfrac{\sqrt{3}}{2}B_{H}$

We need to calculate the true angle of dip

Using formula of angle

$\tan\phi'=\dfrac{B_{v}}{B_{H}'}$

Where, $B_{H}$ =vertical magnetic field

Put the value into the formula

$\tan\phi'=\dfrac{2B_{v}}{\sqrt{3}B_{H}}$

$\tan 45=\dfrac{2}{\sqrt{3}}\tan\phi$

$\tan\phi=\dfrac{\sqrt{3}}{2}$

$\phi=\tan^{-1}\dfrac{\sqrt{3}}{2}$

$\phi=40.89^{\cicrl}$

Hence, The true angle of dip is 40.89°.

Answer 2

Answer:

the true angle at dip - 40.89

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