A magnetizing force of 360 Am^-1 produces a magnetic flux density of 0.6 T in a ferromagnetic material. The susceptibility of the material is
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հίί ʍαtε_______✯◡✯
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_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯it's given that A magnetizing force of 360 Am^-1 produces a magnetic flux density of 0.6 T in a ferromagnetic material.
▶we know that
♦permeability = flux density / magnetising force
▶But Permeability = relative x permeability of free space
So,
B / H = ur * 4pi x 10^-7
0.6 / 360 = ur * 4 pi x 10^-7
▶Susceptibility = ur - 1
THE SUSCEPTIBILITY OF MATERIAL IS ur - 1
_____________________________★
hope it helps!!
★BRAINLY★
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯it's given that A magnetizing force of 360 Am^-1 produces a magnetic flux density of 0.6 T in a ferromagnetic material.
▶we know that
♦permeability = flux density / magnetising force
▶But Permeability = relative x permeability of free space
So,
B / H = ur * 4pi x 10^-7
0.6 / 360 = ur * 4 pi x 10^-7
▶Susceptibility = ur - 1
THE SUSCEPTIBILITY OF MATERIAL IS ur - 1
_____________________________★
hope it helps!!
★BRAINLY★
Answered by
14
The answer is 1329
Explanation:
Given magnetizing force (H) 360A/m
Magnetic flux density (B) 0.6 T
μ0μr=B/H
Then we get μr
Then we substitute μr=(1+χ)
χ = susceptibility which is asked to find
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