Question

a main raises 100kg from the floor to a height of 2m in 2.5second what is the work done and the 0ower developed

Answer 1

Provided that:

• Mass = 100 kg
• Height = 2 m
• Time = 2.5 seconds

To calculate:

• Work done
• Power developed

Solution:

• Work done = 2000 Joules
• Power developed = 800 Watts

Using concepts:

• Work done formula
• Power formula
• Force formula

Using formulas:

• W = Fs
• P = W/t
• F = ma

Where, a denotes acceleration, W denotes work done, F denotes force, s denotes displacement or distance or height, m denotes mass, t denotes time taken and P denotes power.

Knowledge required:

• g denotes acceleration due to gravity, the value of g is 9.8 m/s sq. but we can take it in approx too as 10 m/s sq. according to the situation.

Required solution:

~ Firstly let us calculate the force by using suitable formula!

➝ Force = ma

➝ F = ma

➝ F = 100(10)

➝ F = 1000 N

➝ Force = 1000 N

~ Now let us calculate work done by using suitable formula!

➝ Work done = Force × displacement

➝ W = fs

➝ W = 1000(2)

➝ W = 2000 J

➝ Work done = 2000 Joules

~ Now let us calculate the power by using suitable formula!

➝ Power = Work done/time

➝ P = W/t

➝ P = 2000/2.5

➝ P = 20000/25

➝ P = 4000/5

➝ P = 800 Watts

➝ Power = 800 Watts $\:$

Answer 2

Corrected question:

• A main raises 100kg from the floor to a height of 2m in 2.5second. What is the work done and the power developed?

Information given to us:

• A man raised 100kg.
• Height is of 2m
• Time taken is 2.5 s

What we have to solve:

• What is the work done and power developed?

Let's start now:

We would be finding out the force too because it's the main step to find out work done and power.

$\:$

$\pink \bigstar \: \underline{ \underline { \bf{Formulas \: needed \: to \: solve :- }}}$

• $\red{ \boxed{ \sf{Work \: = \: Force \times displacement}}}$
• $\red{ \boxed{ \sf{Force \: = \ Mass \times Acceleration}}}$
• $\red{ \boxed{ \sf{Power \: = \: \dfrac{Work}{Time} }}}$

$\pink \bigstar \: \underline{ \underline { \bf{Finding \: out \: force:- }}}$

Substituting the values in the formula of force,

$: \longmapsto \: \sf{Force \: = \: 100 \times 10}$

$: \longmapsto \: \boxed{ \bf{Force \: = \: 1000N}}$

Always remember that force is measured in Newton.

$\pink \bigstar \: \underline{ \underline { \bf{Finding \: out \: work \: done:- }}}$

Substituting the values in the formula of work done,

We already have,

• Force is 1000N
• Displacement is 2m

$: \longmapsto \: \sf{Work \: = \: 1000 \times 2}$

$: \longmapsto \: \boxed{\bf{Work \: = \: 2000J}}$

Always remember that work done is measured in Joules.

$\pink \bigstar \: \underline{ \underline { \bf{Finding \: out \: power :- }}}$

We already have,

• Work done is 2000J
• Time is 2.5s

Substituting the values in the formula of power,

$: \longmapsto \: \sf{Power \: = \: \dfrac{2000}{2.5} }$

• Removing decimal point,

$: \longmapsto \: \sf{ Power \: = \: \dfrac{2000 \times 10}{25} }$

$: \longmapsto \: \sf{ Power \: = \: \dfrac{20000}{25} }$

• Reducing it to lowest terms,

$: \longmapsto \: \sf{ Power \: = \: \dfrac{ \cancel{20000}}{ \cancel{25}} }$

$: \longmapsto \: \sf{Power \: = \dfrac{4000}{5}}$

• Dividing 4000 with 5,

$: \longmapsto \: \sf{ Power \: = \: \cancel \dfrac{4000}{5}}$

$: \longmapsto \: \boxed{ \bf{ Power = \:800W}}$

Always remember that power is measured in watts.