A mains kettle has a power rating of 1.15 kW. What current does it use?
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here, I is the current that will flow when the kettleis turned on, V is the electrical supply voltage. Then, we get: I=P/V=(2∙〖10〗^3 W)/(230 V)=8.7 A. b) Since, the current that will flow when thekettle is turned on is 8.7 A we need to include 13 A fuse in the circuit of the kettle.
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