Question

A malai chum_chum sweet contains sugar syrup 25%of it's volume find how much syrup would be found in 100 such malai chum chum each shaped like a cylinder with two hemispherical ends with length 4cm and diameter 1.4cm respectively​

Answer 1

Answer:

kya hai ye?...................

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Answer 2

The volume of syrup present in such 100 malai chum chum will be 190 cm³.

Step-by-step explanation:

The volume of a cylinder with two hemispheres at each end is given by

$V = \frac{4}{3}\pi r^{3} + \pi r^{2}h$

Now, r = 0.7 cm and h = 4 cm {As diameter is 1.4 cm}

So, $V = \frac{4}{3}\times \frac{22}{7}\times (0.7)^{3} + \frac{22}{7}\times (0.7)^{2} \times 4$

⇒ V = 1.44 + 6.16

⇒ V = 7.6 cm³

Now, volume of such 100 malai chum chum will be 7.6 × 100 = 760 cm³.

If 25% of a malai chum chum sweet is sugar syrup, then the volume of syrup present in such 100 malai chum chum will be $760 \times \frac{25}{100} = 190$ cm³. (Answer)