Question

(A man 1.73 m tall
is standing few meters away from the tower of height
91.8 m on the same level of the ground. If he finds the
angle of elevation of top of the tower to be 60°, how far
is he from the foot of the tower? Find it.)
​

Answer 1

Answer:

27

Given that, a man, 1.7 m tall, standing at the foot of a tower sees the top of building that is 50 m away from the foot of the tower. The angle of elevation is 60

o

. On climbing the tower, he sees the angle of elevation as 50

o

.

To find out: The height of the tower.

On the basis of the given information, we can drawn the figure shown above.

Here,

Height of the building =PQ

Height of the tower =AC

The distance between the building and the tower, AP=50 m

From the right △BRQ,

RQ=BR×tan60

o

=50×1.73=86.5

PQ=PR+RQ=1.7+86.5=88.2

Thus, the height of the builiding is about 88.2 m.

From right △DTQ,

QT=DT×tan50

o

=50×1.19=59.5

AC=PS=PQ(QT+TS)

⇒ AC=88.2−(59.5+1.7)

⇒ AC=88.2−61.2=27 m

Hence, the height of the tower is about 27 m.

Step-by-step explanation:

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