a man 180 cm tall stands 4.5 metre in front of a large vertical plane mirror . then the angle subtended at the eye by his image in the plane mirror is
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The horizontal distance of the virtual image from the eye = 4.5 + 4.5 = 9 m
The height of the image = 1.80 m
Angle subtended at the eye = Tan⁻¹ 1.80/9 = Tan⁻¹ 0.20 = 11.3 deg
The height of the image = 1.80 m
Angle subtended at the eye = Tan⁻¹ 1.80/9 = Tan⁻¹ 0.20 = 11.3 deg
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1
Answer:
11.3%
Explanation:
The horizontal distance of the virtual image from the eye = 4.5 + 4.5 = 9 m
The height of the image = 1.80 m
Angle subtended at the eye = Tan⁻¹ 1.80/9 = Tan⁻¹ 0.20 = 11.3 deg
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