Question

A man 20 years elder to his son. After 10 years, his age becomes twice the age of his son. Find their present ages

Answer 1

Answer:

8

Step-by-step explanation:

Ans: Present age of son: 8

Let x be the sons present age

Father age : x+20

In two years, father age is three times sons age

x+20+2= 3(x+2)

x=8

Answer 2

Answer:

10 and 30 years old.

Step-by-step explanation:

"s" is age of son;

"f" is age of father.

f = 20 + s

f + 10 = 2(s + 10)

2s + 20 = 20 + s + 10

2s - s = 10

(30 + 10) = 2(10 + 10)

40 = 40

Son is 10 years old.

Father is 30 years old.