A man 2m high walks at a uniform speed of 6m/min away from the lamp post 5m high . Find the rate at which the length of his shadow increases
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let shadow be s long after 1 min. dist trvlf = 6 m. We have two similar rt ld ∆s s/2=(s+6)/5 gives s=4. When t=0 s=0. Hence speed of shadow is 4m per min.
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The rate of increase of length of shadow is 4m/min
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