Question

A man a woman and a boy individually can complete a certain work in 6, 8 and 24 days respectively how many boys assist one man and two women such that the work is completed in 2 days

Answer 1

Step-by-step explanation:

A man and 2 women complete work in a day =

1/6 + 2×1/8 = 10/24 of work

A man and 2 women complete work in 2 days =

2 × 10/24 = 10/12 of work .... (2)

Total remaining work for some number of boys =

1 - 10/12 = 2/12 of work

Therefore 2/12 of the work is to be finished by boys only so that the work complete in 2days only

Now subtracting equation 2 from equation 1 we get :

A boy complete work in 2days = 11/12 - 10/12 = 1/12 of work

So remaining work is completed by number of boys , so that work can complete in 2days only =

$\frac{ \frac{2}{12} }{ \frac{1}{12} }$

= 2 boys.

Thus 2 boys must assist one man and two women such that the work is completed in 2 days.

Hope it helps

Answer 2

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