Question

a man aacelerates from rest at a rate of 5m/s^2 for 10 sec.He then retards with 1m/s^2 and ces to rest find max velocity and total distance covered by him​

Answer 1

Answer:

Maximum velocity achieved is 50 m/s, and total distance travelled is 1250m + 250m = 1500m

Explanation:

First half of the question:

Initial velocity (u) = 0 m/s

Time (t) = 10s

Acceleration (a) = 5 m/s²

Final velocity (v) = ?

Distance (s) = ?

Distance covered in the first half:

s = ut + 1/2at²

s = 0 + 2.5 * 100 = 250m

Distance (s) = 250m

v = u + at

v = 0 + 50 = 50 m/s

Second part of the question:

Acceleration (a) = -1 m/s²

Initial velocity (u) = 50 m/s

Final Velocity (v) = 0 m/s

Time (t) = ?

Distance (s) = ?

a = v-u/t

t = v-u/a

t = -50/-1

Time (t) = 50s

s = ut + 1/2at²

s = 2500 + (-1/2 * 2500)

s = 2500 - 1250

s = 1250m

So, maximum velocity achieved is 50 m/s, and total distance travelled is 1250m + 250m = 1500m

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Lilac584