A man accelerates on a straight road from rest to a speed of 200km/hr in 30second assuming uniform acceleration of man through out , what is the distance covered in this time
Answers
Answered by
5
Answer:
Answer is 100 km
consider 30 second as 1/2 minute
distance = speed × time
so, 200×1/2= 100
100 km answer
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Answered by
10
ANSWER :
Given :
▪ Initial speed = zero (i.e. rest)
▪ Final speed = 200kmph
▪ Time interval = 30s
To Find :
▪ Distance covered by man in the given interval of time.
Concept :
✏ First we have to find out acceleration afterthat we can calculate distance travelled.
✏ Since acceleration is constant throughout the whole journey we can apply equation of kinematics directly.
✏ Acceleration is defined as the ratio of change in velocity to the time interval.
✏ It is a vector quantity.
Mathematically,
☞ a = (v - u)/t
Conversion :
✴ 1kmph = 5/18mps
✴ 200kmph = 200×5/18 = 55.56mps
Calculation :
✒ S = ut + (1/2)at^2
✒ S = (0×t) + (1/2)(v - 0/t)t^2
✒ S = 0.5×(vt)
✒ S = 0.5×55.56×30
✒ S = 833.4m
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