A man age is x in the year x square, If the man died in 1871. Find the year of birth.
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Answered by
1
First of all find out the perfect square just before 1871
Which is 1849
So in 1849 he will be 43 years old because 43^2 = 1849
When we subtract 43 from 1849 we will get his year of birth,which is 1806
HOPE IT HELPS
Which is 1849
So in 1849 he will be 43 years old because 43^2 = 1849
When we subtract 43 from 1849 we will get his year of birth,which is 1806
HOPE IT HELPS
Answered by
1
Hey friend!!!!
Here's the answer you are looking for
Since the man died in 1871, x sqaure must be less than 1871 as in the year x square he was alive.
So
x^2 < 1871
Thus
x must be less than root over of 1871
i.e.,
x < √1871
x < 43.255057
So x must be below 43 years.
Thank you ☺️
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Since the man died in 1871, x sqaure must be less than 1871 as in the year x square he was alive.
So
x^2 < 1871
Thus
x must be less than root over of 1871
i.e.,
x < √1871
x < 43.255057
So x must be below 43 years.
Thank you ☺️
★★ HOPE THAT HELPS ☺️ ★★
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