Math, asked by naanuz5698, 1 year ago

A man aged 27 married a women aged 24, he dies at the age of 81 and she dies at the age of 91. For what fraction of his life is the man married? For what fraction of her life is the women a widow?

Answers

Answered by Blaezii
1

Answer:

2/3

1/7

Step-by-step explanation:

Man married at age of 27

Man died at at the age of 81

Man married for = 81 -27 = 54  Years

Man married/ Man Life = 54/81  = 2/3

Women married at age of 24

so women is 3 year (27-24) younger than man

Man died at 81 age at that time woman age = 81-3 = 78

at 78 age woman widowed

Woman died at age of 91

Woman remain widowed for = 91 -78 = 13 years

Widow woman/Woman Life = 13/91 = 1/7

Answered by Anonymous
2

Answer:

Hey mate,here is your solution.

hope it will help you

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