Math, asked by Krish23606, 6 months ago

A man aged 27 marries a woman aged 24,he dies at the age of 81and she dies at the age of 91. For what fraction of his life is the man married ? For what fraction of her life is the woman a widow?​

Answers

Answered by anurags8882975
4

Answer:

1/7

Step-by-step explanation:

Man married at age of 27

Man died at at the age of 81

Man married for = 81 -27 = 54 Years

Man married/ Man Life = 54/81 = 2/3

Women married at age of 24

so women is 3 year (27-24) younger than man

Man died at 81 age at that time woman age = 81-3 = 78

at 78 age woman widowed

Woman died at age of 91

Woman remain widowed for = 91 -78 = 13 years

Widow woman/Woman Life = 13/91 = 1/7

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