Math, asked by 200jass, 10 months ago

a man aged 27 marries a woman aged 24, he dies in the age of 81 and she dies at the age of 91. for what fraction of his life is the man married. for what fraction of her life is the woman a widow​

Answers

Answered by kvjkarthik
77

Answer:

Man's age = 27 years & Woman's age = 24 years

Age of death of man = 81 years and

Age of woman when husband died = 78 years

Age of death of woman = 91 years

Fraction of life man is married = 81-27/81 = 54/81

Fraction of woman's life the woman is a widow = 91-78/91 = 13/91

Answered by amitnrw
111

Answer:

2/3

1/7

Step-by-step explanation:

Man married at age of 27

Man died at at the age of 81

Man married for = 81 -27 = 54  Years

Man married/ Man Life = 54/81  = 2/3

Women married at age of 24

so women is 3 year (27-24) younger than man

Man died at 81 age at that time woman age = 81-3 = 78

at 78 age woman widowed

Woman died at age of 91

Woman remain widowed for = 91 -78 = 13 years

Widow woman/Woman Life = 13/91 = 1/7


safa283: u r Brilliantly explained. thank u so much
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