Math, asked by pushpendrapareek61, 11 months ago

a man aged 27 marries a woman aged 24, he dies in the age of 81 and she dies at the age of 91. for what fraction of his life is the man married. for what fraction of her life is the woman a widow​A man aged 27 marries a woman aged 24, he dies in the age of 81 and she dies at the age of 91. for what fraction of his life is the man married. for what fraction of her life is the woman a widow​


preetuchauhan9898ac: Plz ans this

Answers

Answered by amitnrw
30

Answer:

2/3

1/7

Step-by-step explanation:

Man married at age of 27

Man died at at the age of 81

Man married for = 81 -27 = 54  Years

Man married/ Man Life = 54/81  = 2/3

Women married at age of 24

so women is 3 year (27-24) younger than man

Man died at 81 age at that time woman age = 81-3 = 78

at 78 age woman widowed

Woman died at age of 91

Woman remain widowed for = 91 -78 = 13 years

Widow woman/Woman Life = 13/91 = 1/7

Answered by Anonymous
16

Answer:

hey mate,here is your solution.

hope it will help you.

Attachments:
Similar questions