Question

A man aged 27 marries a women aged 24 , he dies at a age 81 and she dies at the age of 91 for what fraction of her life is the woman widow ?
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Answer 1

Answer:

Step-by-step explanation:

Man age at time of marriage = 27 years

Man age at time of death = 81 years

His period of married life = 81-27= 54 years

So, fraction of his married life = 54/81 = 2/3

Now, difference of age on their marriage = 27-24= 3years

Difference of age on their death = 91-81 = 10 years

Total = 3+10=13 years

So, fraction of her life as widow = 13/91 =1/7

Answer 2

Answer:

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