A man and a boy complete a work in 24 days. If for the last 6 days man does work alone then it is completed in 26 days. How long boy take to work alone.
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Answer:
(1/m +1/b)= 1/24
6 days before 26 days =20 days
so work done in 20 days = 20*(1/24) =5/6
so work left =1/6
1/6 of the work is done by the man in 6 days so time required by the man to complete the work alone
= 1/6 work in 6 days
1 work = 6*6 =36 days
so replacing m by 36
(1/36+1/b) = 1/24
so 1/b =1/72 therefore b = 72 days
b-boy
m-man
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