Math, asked by swethabalasaria5785, 11 months ago

A man and a boy complete a work in 24 days. If for the last 6 days man does work alone then it is completed in 26 days. How long boy take to work alone.

Answers

Answered by aryan987114
1

Answer:

(1/m +1/b)= 1/24

6 days before 26 days =20 days

so work done in 20 days = 20*(1/24) =5/6

so work left =1/6

1/6 of the work is done by the man in 6 days so time required by the man to complete the work alone

= 1/6 work in 6 days

1 work = 6*6 =36 days

so replacing m by 36

(1/36+1/b) = 1/24

so 1/b =1/72 therefore b = 72 days

b-boy

m-man

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