Physics, asked by wanishakir2020, 4 months ago

A man arrived at Delhi railway station and wanted to go to his relatives house 10km away from the station.He hired a taxi to reach the destination.The driver followed a long path of 25 km to reach the destination in one hour and charged from the man for 25km.calculate the average speed and average velocity of the taxi​

Answers

Answered by hareem23
0

Answer:

Average speed=Total distance/time=25kmph

avg velocity=net displacement/time=10kmph

 \huge \red{brainlist \: plz}

Answered by Rameshjangid
0

Answer:

The average speed and the average velocity of the taxi are not the same, since velocity takes into account the direction of motion.

Explanation:

To calculate the average speed of the taxi, we need to use the formula:

average speed = total distance / total time

In this case, the total distance traveled by the taxi is 25 km and the time taken to cover this distance is 1 hour. Therefore, the average speed of the taxi is:

average speed = 25 km / 1 hour = 25 km/hour

To calculate the average velocity of the taxi, we need to take into account the direction of motion as well. Velocity is a vector quantity and includes both the magnitude (speed) and the direction of motion. Since we do not have information about the direction of motion, we will assume that the taxi was moving in a straight line from the railway station to the destination.

In this case, the displacement of the taxi is 10 km (the straight-line distance from the railway station to the destination). The time taken to cover this distance is 1 hour. Therefore, the average velocity of the taxi is:

average velocity = displacement / time = 10 km / 1 hour = 10 km/hour

Note that the average speed and the average velocity of the taxi are not the same, since velocity takes into account the direction of motion.

To learn more about similar question visit:

https://brainly.in/question/547762?referrer=searchResults

https://brainly.in/question/6960814?referrer=searchResults

#SPJ6

Similar questions