Question

A man о as is four times as old his Son. After 20 years he will be twice as old his son. Find their present ages . as a UREL​

Answer 1

Consider the present age of son =x years

So the present age of father =4x years

After 20 years

Age of son =(x+20)years

Age of father =(4x+20)years

Based on the condition

4x+20=2(x+20)

By further calculation

4x+20=2x+40

2x=20

So we get

x=10

So the present age of son =10 years

Present age of father =4×10=40 years.

Was this answer helpful?