A man at the top of a 100 m high tower sees a car moving towards the tower at an angle of depression of 30°. After some time, the angle of depression becomes 60°. The distance travelled by the car during this time interval is:
10√3 m
100√3/3 m
200√3/3 m
200√3 m
Answers
Answered by
0
Answer:
Answer
Correct option is
B
3
200
3
In ΔABD
tan60
0
=
x
100
⇒x=
3
100
3
m
In ΔABC
tan30
0
=
x+y
100
⇒
3
1
=
100
3
+3y
100×3
⇒y=
3
200
3
m
Answered by
0
a man at the top of a 100m
the towers at an angle of depression of 30°.
the angle of depression become 60°.
the distance travelled by the car during this time interval is=200√3/3m
Similar questions