Question

A man borrowed 36,00 at 12% interest per annum. At the end of six years he repaid
2,400 and a watch for the balance amount. Find the cost of the watch.​

Answer 1

InterestI=P0rA=P0+I=P0+P0r=P0(

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)I is the interest

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)I is the interestA is the end amount: principal plus interest

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)I is the interestA is the end amount: principal plus interestP0 is the principal (starting amount)

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)I is the interestA is the end amount: principal plus interestP0 is the principal (starting amount)r is the interest rate (in decimal form. Example: 5% = 0.05)

Simple One-time InterestI=P0rA=P0+I=P0+P0r=P0(1+r)I is the interestA is the end amount: principal plus interestP0 is the principal (starting amount)r is the interest rate (in decimal form. Example: 5% = 0.05)

Answer 2

Answer:

3600×12×6÷100= 2592=intrest

he gave 2400 and a watch

so 3600+2592 =6192

6192-2400=4792

the cost of ⌚ watch = 4792