Question

a man borrowed a sum of money from a bank on 28 April at 6% per annum he paid back rupees 2048 and cleared his Dept on 21st September find the sum borrowed​

Answer 1

▂ ▄ ▅ ▆ ▇ █ SOLUTION █ ▇ ▆ ▅ ▄ ▂

☆GIVEN☆

• RATE=6%

☆FIND

• SUM OF MONEY

☆LET

• The sum of money be X
• at first we have calculated time

☆Time from 28 to 21 september

• April=2days
• may=31days
• June=30days
• July=31days
• August=30days
• September=21days

☆here we have to sum of the above days

• sum of days=2+31+30+31+30+21=145days
• convert the days into year
• 145/365years

☆According to the above information☆

$⟶si = \frac{p \times t \times r}{100} \\ \\ ⟶si = \frac{x \times 145 \times 6}{100 \times 365} \\ \\ ⟶si = \frac{174x}{7300}$

☆he paid back 2048₹

$↪amount = p + si \\ \\ ↪amount = x + \frac{174x}{7300} \\ \\ ↪amount = \frac{7300x + 174x}{7300} \\ \\ ↪amount = \frac{7474x}{7300}$

Hence

• the sum of money

$⇒ \frac{7474x}{7300} = 2048 \\ \\ ⇒7474x = 7300 \times 2048 \\ \\ ⇒x = 2000.32$