Question

A man borrowed a sum of Rs. 10000 for 1 year at 37.5% per annum compounded every four months. Find the amount that he will have to repay at the end of 1 year. Please answer it is urgent i will surely mark as brainliest ​

Answer 1

For the first year

PI =10,000,R=5%

A =10,000(1+ 1005 )=10000× 100105

=Rs.10500

At the end of the first year he repay 35% of the sum borrowed so he repay the amount=10000×10035 =Rs3500

left amt=10000−3500=Rs.7000

For the second year

P 2=Rs.7000, R=5%

A 2=7000(1+ 1005)=7000× 100/105 =Rs.7350

At the end of the second year he repay 42% of the sum borrowed so he repay the amt=10000×100/42=Rs.4200

Left amt=7350−4200=Rs.3150

For the Third year

P 3 =Rs.3150,R=5%

A 3 =3150(1+1005) =3150× 100/105

=Rs.3307.50

Hence he pay Rs. 3307.50 at the end of the third year in order to clear the debt.

hope it helps