Question

A man borrowed a sum of Rs. 10000 for 1 year at 37.5% per annum compounded every four months. Find the amount that he will have to repay at the end of 1 year​

Answer 1

Answer:

10000+37,-65588525558yygiurtjotfjfifif

Answer 2

Answer:

Given:

Principal = rs.10000

Time = 1 year

Rate = 37.5%

Find:

Amount he had to paid after an year

Solution:

Here, convert the Time and Rate according the Question...

we, know that

Time = 1 year = 12months

So,

$\rm \implies \dfrac{ \cancel{12}}{ \cancel{4}} = 3 \: months$

Hence,

Time = 3 months

Now,

Rate = 37.5%

$\rm \implies \dfrac{ \cancel{37.5}}{ \cancel{3}} = 12.5\%$

Hence, Rate = 12.5%

Now, we know that

$</p><p>\underline{ \boxed{ \rm \color{green}Amount = P \times {\bigg(1 + \dfrac{R}{100} \bigg)}^{n} }} </p><p>$

where,

• P = rs. 10000
• R = 12.5%
• n = 3months

So,

$\rm \to Amount = P \times {\bigg(1 + \dfrac{R}{100} \bigg)}^{n}$

$\rm \to Amount = 10000 \times {\bigg(1 + \dfrac{12.5}{100} \bigg)}^{3}$

now, take the L.C.M

$\rm \to Amount = 10000 \times {\bigg( \dfrac{100 + 12.5}{100} \bigg)}^{3}$

$\rm \to Amount = 10000 \times {\bigg( \dfrac{112.5}{100} \bigg)}^{3}$

$\rm \to Amount = 10000 \times 1.423828125$

$\rm \to Amount = rs.14238.28125$

Hence, The sum of money He had to pay after an year will be rs.14238.28125