Math, asked by Anonymous, 11 months ago

A man borrowed Rs 15000/- at the rate of 24% SI and to clear the debt after 6years, much he has to return?

Answers

Answered by Anonymous
17

Using the Basic Formula:

\huge\boxed{\sf{SI= \frac{(P \times R \times T)}{100}}}

Given:

P = 15000

T = 6 Years

R = 24%

Simple Interest (S.I.):

\implies (15000 × 24 × 6) / 100

\implies (15000 × 144) / 100

\implies (2160000 / 100)

\implies Rs. 21600

Therefore:

Total interest = 21600

Total repayment:

\implies S.I + Principal amount

\implies 21600 + 15000

\implies Rs. 36600

Final answer: Rs. 36600


Anonymous: Ty Bro❤️
Swetha02: Awesome answer, didi❤️
Anonymous: Tysm Siso❤️
Answered by Anonymous
7

Heya!

Here is ur answer...

GIVEN,

P= 15000

T= 6 years

R = 24%

Now,

SI = PTR/100

SI = 15000 x6x24/100

SI = 21600

And,

A = P+I

A = 15000+21600

A = 36600

Therefore, he has to return = 36600

Hope it helps

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