Question

A man borrowed Rs 20000 for 2 years at 8% per year compound interest. Calculate
a) The final amount at the end of second year
b) The compound interest of two years

Answer 1

Answer:

Question:-

  · A man borrowed Rs 20000 for 2 years at 8% per year compound interest.

To find:-

 

  · The final amount at the end of second year

  ·  The compound interest of two years

Solution:-

⇒ ∴ Interest of the first year = P × R × T/ 100

⇒ ∴ Interest of the first year = 20000 × 8 × 1 /100

⇒ Interest of the first year = 16000 / 100 = 1600

⇒  ∴ Amount after one year

⇒  Principal for second year = Rs. 20,000 + Rs. 1,600 = Rs. 21,600

∴ Interest for second year = (21,600 × 8 ×1)/100 = = 216 × 8 = Rs. 1728

⇒ Final amount at the end of second year  = Rs. (21,600 + 1728) = Rs. 23,328

⇒ Interest of two years = Rs. 23,328 – Rs. 20,000 = Rs. 3,328.

Answer:-

a)The final amount at the end of second year is  Rs. 21,600  

b) The compound interest of two years is Rs. 3,328.

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Answer 2

Step-by-step explanation:

if one of the zeros of the quadratic polynomial is negative then other then it has no linear term