a man borrowed rs 3000 at8% interest per annual. at the end of a year.he paid rs1200 partly an intrest for the first partly an interest reduce the dept. at the end of second year he paid rs 1300 find the some....
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Hi ,
Principal = P = Rs 2400
Rate of interest ( I ) = 12%
Time = T = 2 1/2 years = 5 /2 years
Amount = A
We know that ,
A = P ( 1 + TR /100 )
= 2400[ 1 + (5 × 12)/(2 × 100 )]
= 2400 × [ ( 100 + 60 ) /200 ]
= 2400 × 160 /200
A = RS 3120
According to the problem given ,
1200 + cost of cow = A
Cost of the cow = 3120 - 1200
= Rs 1920
Principal = P = Rs 2400
Rate of interest ( I ) = 12%
Time = T = 2 1/2 years = 5 /2 years
Amount = A
We know that ,
A = P ( 1 + TR /100 )
= 2400[ 1 + (5 × 12)/(2 × 100 )]
= 2400 × [ ( 100 + 60 ) /200 ]
= 2400 × 160 /200
A = RS 3120
According to the problem given ,
1200 + cost of cow = A
Cost of the cow = 3120 - 1200
= Rs 1920
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