Math, asked by SacarBist08, 3 months ago

a man borrowed rs 30000 for 2 years at 10% per year annum compounded annually. he paid only half of the principal at the end of 2 years. he paid that remaining principal and interest at the same rate at the end of next years. how much amount did he pay at the last to clear debt​

Answers

Answered by varchaswjaiswal7299
2

Step-by-step explanation:

(30000×2×10)/100

6000 rs

36000 rs he have to pay

hopefully it will help you

Answered by rejiprd49
4

Answer:

Step-by-step explanation:

principal amount (P) = Rs 30000

time (T) = 2 years

Rate (R) =10%

Using the formula of compound interest we found that the interest the man had to pay is Rs 6300. The total amount of money man had to pay is (Principal + Interest Accrued)  Rs 30000 + Rs 6300. However, man paid only half of the principal i.e only Rs 15000. So, the amount he have to pay for next 2 years is Rs 15000 + Rs 6300(=Rs 21300).

Thus for the next 2years

P=21300

T=2 yrs

R=10%

Compound interest accrued = Rs 4473 (by using C.I formula)

The amount he had to pay at last = principal(Rs21300) + Interest(Rs4473)

                                                         = Rs 25773

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