Question

A man borrowed Rs x every year at 10% p.a. C.I. If at the end of 3 years he pays Rs. 3641 in all, find the value of x​

Answer 1

Step-by-step explanation:

Answer:

X = Rs. 27355

Solution:

Given, sum = X,

time (t) = 3 years and

rate (r) = 10%

If P be the amount to be paid after 3 years on the sum X in a compound interest of rate 10% per annum, we have

P = X (1 + r/100)ᵗ

or, P = X (1 + 10/100)³

or, P = X (1 + 1/10)³

or, P = X (11/10)³

or, X = P (10/11)³

Here given P = Rs. 36410

Then X = Rs. 36410 (10/11)³

≈ Rs. 27355

Answer 2

Given:

• A man borrow Rs x in every year at 10% p.a. Compound Interest .
• He pays Rs 3641 after 3years

To Find:

• What is the value of x?

Main Formula :

• ${\small{\sf{Compound \ Interest = P \bigg\lgroup 1 + \dfrac{R}{100} \bigg\rgroup ^n }}}$
• ${\small{\sf{Amount = Principle + Interest}}}$

Solution :

${\small{\tt{C.I. = x \bigg\lgroup 1 + \dfrac{1{ \cancel0}}{10{ \cancel0}} \bigg\rgroup ^3}}}$

${\small{\tt{\implies{C.I. = x \bigg\lgroup \dfrac{11}{10} \bigg\rgroup ^3}}}}$

${\small{\tt{\implies{C.I. = x \bigg\lgroup \dfrac{1331}{1000} \bigg\rgroup }}}}$

${\small{\tt{\implies{C.I. = 1.331x}}}}$

We know that

${\small{\tt{\dashrightarrow{Amount = Principle + Interest}}}}$

${\small{\tt{\dashrightarrow{3641 = x + 1.331x }}}}$

${\small{\tt{\dashrightarrow{3641 = 2.331x}}}}$

${\small{\tt{\dashrightarrow{x = \dfrac{3641}{2.331}}}}}$

${\small{\tt{\dashrightarrow{x = 1561.99 \approx 1562 \: rs}}}}$