Question

A man borrowes ₹500'and payback after 18 months at 14%pa find si

Answer 1

★ Given :-

• Principal = Rs. 500
• Rate = 14 %
• Time = 18 months

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★ To Find :-

• Simple Interest = ?

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★ Solution :-

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∓ Here, it is given that, Principal is Rs. 500. Rate of Interest is 14 % per annum. Time is 18 months. And, we have to find the value of Simple Interest .

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• Now, let's solve step by step -----

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$\bull \: \sf \pmb{Simple \: Interest = \frac{P \times R \times T}{100} } \\ \\ \dashrightarrow \: \sf{S.I = \frac{500 \times 14 \times 18}{100} } \\ \\ \dashrightarrow \: \sf{S.I = \frac{5 \times 14 \times 18}{1} } \\ \\ \dashrightarrow \: \sf{S.I =5 \times 14 \times 18} \\ \\ \dashrightarrow \: \sf{S.I =5 \times 252} \\ \\ \dashrightarrow \: \sf \pmb{S.I =Rs. \: 1260}$

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★ Hence :-

• Simple Interest = Rs. 1260

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Answer 2

Answer:

➥ Given-:

• Principal (P) = Rs. 500
• Rate (R) = 14% p.a
• Time (T) = 18 months

➥ To Find-:

• Simple Intrest (S.I) = ?

➥ Using Formula-:

$\bigstar \: \boxed{ \sf{S.I = \frac{P × R × T}{100} }}$

➥ Calculation-:

$\sf{S.I = \frac{P × R × T}{100}} \\ \\ \\ \sf \: \implies \: \frac{5 \cancel{00} \times 14 \times 18}{1 \cancel{00} } \\ \\ \\ \sf \: \implies \: 5 \times 14 \times 18 \\ \\ \\ \boxed{\sf \: \implies \: Rs. \: 1260}$

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➼ FINAL ANSWER-:

S.I = Rs. 1260

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