A man borrows ₹ 10000 at 10 % compound interest per annum. He repays ₹ 3000 at the end of every year. Calculate the amount of loan outstanding at the beginning of the third year
Answers
Sum=Rs.10,000
Sum=Rs.10,000Rate of interest=10%
Sum=Rs.10,000Rate of interest=10%Interest for one year=
Sum=Rs.10,000Rate of interest=10%Interest for one year= 100
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000=
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 100
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year=
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 100
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800Total amount aftre 2 year=8000+800=Rs.8800
Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800Total amount aftre 2 year=8000+800=Rs.8800He pay again rs 3000 then the amount left=8800−3000=Rs.5800
Answer:
Sum=Rs.10,000
Rate of interest=10%
Interest for one year=
100
10000×10×1
=Rs.1000
Total amount=10000+1000=Rs.11000
At the end of first year he pay =30% of 10000=
100
30
×10000=Rs.3000
Amount left=11000−3000=Rs.8000
∴ Interest for second year=
100
8000×1×10
=Rs.800
Total amount aftre 2 year=8000+800=Rs.8800
He pay again rs 3000 then the amount left=8800−3000=Rs.5800