Question

A man borrows ₹ 10000 at 10 % compound interest per annum. He repays ₹ 3000 at the end of every year. Calculate the amount of loan outstanding at the beginning of the third year​

Answer 1

Sum=Rs.10,000

Sum=Rs.10,000Rate of interest=10%

Sum=Rs.10,000Rate of interest=10%Interest for one year=

Sum=Rs.10,000Rate of interest=10%Interest for one year= 100

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000=

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 100

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year=

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 100

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800Total amount aftre 2 year=8000+800=Rs.8800

Sum=Rs.10,000Rate of interest=10%Interest for one year= 10010000×10×1 =Rs.1000Total amount=10000+1000=Rs.11000At the end of first year he pay =30% of 10000= 10030 ×10000=Rs.3000Amount left=11000−3000=Rs.8000∴ Interest for second year= 1008000×1×10 =Rs.800Total amount aftre 2 year=8000+800=Rs.8800He pay again rs 3000 then the amount left=8800−3000=Rs.5800

Answer 2

Answer:

Sum=Rs.10,000

Rate of interest=10%

Interest for one year=

100

10000×10×1

=Rs.1000

Total amount=10000+1000=Rs.11000

At the end of first year he pay =30% of 10000=

100

30

×10000=Rs.3000

Amount left=11000−3000=Rs.8000

∴ Interest for second year=

100

8000×1×10

=Rs.800

Total amount aftre 2 year=8000+800=Rs.8800

He pay again rs 3000 then the amount left=8800−3000=Rs.5800