A man borrows RS. 1000 and agrees to repay with a total interest of Rs. 140 in 12 installments, each installment being less then the proceeding one by RS. 10. What should be his 1st installment
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Let the First Instalment be 'a'.
and second Instalment be '10-a'.
Since it will form an A.P.
The sum of ten Instalments = 10/2[2a + (10-1) (-10)] = 5[2a - 90]
So, 5 [2a-90] = 4000.
= 10a - 450 = 4000.
10a = 4450.
a = 4450/10
a = 445.
First Instalment will be Rs. 445.
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