a man borrows rs 10000 at a compound interest rate of 8% per annum .if he repay 2000 at the end of each year, Find the sum outstanding at the end of the third year .
Answers
Answered by
7
Answer:
c.p of 1 year=10000×108/100
=10800-2000=8800
c.p of 2nd year=8800×108/100=9504-2000=7504
c.p of 3rd year=7504×108/100=8104.32-2000=6104.32
therefore sum outstanding at the end of the third year=6104.32
Similar questions