Math, asked by dracogaming714, 1 day ago

a man borrows rs 16000 at 15% p.a compounded annually. if he repays Rs4500 at the end of each year,how much loan is outstanding against him at the beginning of the third year?

Answers

Answered by mohdamiretw9045
0

Answer:

begining of the third year 27000

Answered by kaushlendrasisodia19
0

Answer:

he pay in 2 years 4500 ×2 =₹9000

amount after 2 year = p(1+R/100)^2 = ₹21160

balance at the beginning of 3rd year = ₹21160-₹9000= ₹ 12160

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