Math, asked by guptashekhar217, 9 months ago

a man borrows rupees 10000 at 5% per annum compound interest hi rupees 35% of the sum borrowed at the end of the first year and 42% of the sum borrowed at the end of the second you how much must he pay at the end of the third year in order to clear the temp​

Answers

Answered by JUSTFLASH999
1

Answer:For the first year

P  

1

​  

=10,000,R=5%

A  

1

​  

=10,000(1+  

100

5

​  

)

      =10000×  

100

105

​  

 

      =Rs.10500

At the end of the first year he repay 35% of the sum borrowed so he repay the amount=10000×  

100

35

​  

=Rs3500

left amt=10000−3500=Rs.7000

For the second year

P  

2

​  

=Rs.7000, R=5%

A  

2

​  

=7000(1+  

100

5

​  

)

      =7000×  

100

105

​  

 

      =Rs.7350

At the end of the second year he repay 42% of the sum borrowed so he repay the amt=10000×  

100

42

​  

=Rs.4200

Left amt=7350−4200=Rs.3150

For the Third year

P  

3

​  

=Rs.3150,R=5%

A  

3

​  

=3150(1+  

100

5

​  

)

      =3150×  

100

105

​  

 

      =Rs.3307.50

Hence he pay Rs. 3307.50 at the end of the third year in order to clear the debt.

Step-by-step explanation:For the first year

P  

1

​  

=10,000,R=5%

A  

1

​  

=10,000(1+  

100

5

​  

)

      =10000×  

100

105

​  

 

      =Rs.10500

At the end of the first year he repay 35% of the sum borrowed so he repay the amount=10000×  

100

35

​  

=Rs3500

left amt=10000−3500=Rs.7000

For the second year

P  

2

​  

=Rs.7000, R=5%

A  

2

​  

=7000(1+  

100

5

​  

)

      =7000×  

100

105

​  

 

      =Rs.7350

At the end of the second year he repay 42% of the sum borrowed so he repay the amt=10000×  

100

42

​  

=Rs.4200

Left amt=7350−4200=Rs.3150

For the Third year

P  

3

​  

=Rs.3150,R=5%

A  

3

​  

=3150(1+  

100

5

​  

)

      =3150×  

100

105

​  

 

      =For the first year

P  

1

​  

=10,000,R=5%

A  

1

​  

=10,000(1+  

100

5

​  

)

      =10000×  

100

105

​  

 

      =Rs.10500

At the end of the first year he repay 35% of the sum borrowed so he repay the amount=10000×  

100

35

​  

=Rs3500

left amt=10000−3500=Rs.7000

For the second year

P  

2

​  

=Rs.7000, R=5%

A  

2

​  

=7000(1+  

100

5

​  

)

      =7000×  

100

105

​  

 

      =Rs.7350

At the end of the second year he repay 42% of the sum borrowed so he repay the amt=10000×  

100

42

​  

=Rs.4200

Left amt=7350−4200=Rs.3150

For the Third year

P  

3

​  

=Rs.3150,R=5%

A  

3

​  

=3150(1+  

100

5

​  

)

      =3150×  

100

105

​  

 

      =c

Hence he pay Rs. 3307.50 at the end of the third year in order to clear the debt.

Hence he pay Rs. 3307.50 at the end of the third year in order to clear the debt.

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