A man borrows two equal sums of money at simple interest. The one
bears interest at 2.5% p.a. and the other at the rate of 3% p.a. After
the end of 11 years, he pays Rs. 77 more to the later than for the former.
Find the sum borrowed.
Answers
Answered by
0
Answer:
Answer
Open in answr app
Correct option is
D
Rs.4250
Solution:-
Let each sum be x.
Given that rate of interest is 11%
Now according to the question-
100×2x×11×9−100×2x×11×7=412.5
99x−77x=412.5×200
⇒22x=82500
⇒x=2282500=3750
Hence the value of each sum is Rs.3750.
Answered by
0
Answer:
Step-by-step explanation:
Similar questions