Question

a man bought 105 chocolates for birthday he distributed the chocolates in students as 3 chocolate for each considering him so after some time some more students came and he distributed 2 chocolates now between each one now if there are 40 persons including him how many students came later?​

Answer 1

Answer:

No. of students who came later = 15

Answer 2

Answer:

hence 12 students came later

Step-by-step explanation:

Let earlier were x students and y students cam later

so  3x+2y=105.........(1)  all chocolates

and  x+y+1=40  all persons

x+y=39

or   3x+3y=117.........(2)

Subtracting (1) from(2)

y=117-105=12

thus y=12

hence 12 students came later