Question

A man bought 120 oranges
at 6 a rupee and 120 more at a 5 rupee. On transportation 16 oranges were spoiled. He sold the remaining oranges at 4 a rupee. Find the profit or loss percent.​

Answer 1

Answer:

29.1%

Step-by-step explanation:

C.P = Cost Price

S.P = Selling Price

S.P of each orange = ₹ 4

C.P of oranges costing 6 rupees = 120 × 6

= ₹ 720

C.P of oranges costing 5 rupees = 120 × 5

= ₹ 600

Total number of oranges = 120 + 120

= 240

Number of oranges after transportation = 240 - 6

= 234

Total C.P = 720 + 600

= ₹ 1320

Total S.P = 4 × 234

= ₹ 936

As,

C.P is greater than S.P.

Therefore,

Man has suffered loss.

Therefore,

Loss percent = 100 - (S.P/C.P × 100)

= 100 - (1320/936 × 100)

= 100.0 - 70.9

= 29.1 %