Math, asked by badalkushwahak2010, 1 year ago

A man bought 18 oranges for a rupee and sold them at 12 oranges for a rupee.What is the profit %.

Answers

Answered by ashad90
3
CP of 18 oranges = SP of 12 oranges
= ₹1
SP of 1 orange = ₹1 /12
so, SP of 18 oranges =18×1/12=₹3/2
profit= SP-CP
=3/2-1=1/2
P%=P/CP×100%
=1/2×100
=50%
Answered by isyllus
3

Answer:

The profit is equal to 50%

Step-by-step explanation:

A man bought 18 oranges for a rupee and sold them at 12 oranges for a rupee.

We will find CP (cost price) and SP (selling price) of 1 oranges.

Cost of 18 oranges = Rs 1

Cost of 1 orange =\dfrac{1}{18}

Selling price of 12 oranges = Rs 1

Selling price of 1 orange =\dfrac{1}{12}

Profit = SP -SP

Profit =\dfrac{1}{12}-\dfrac{1}{18}=\dfrac{1}{36}

Now we will find profit percentage

P% =\dfrac{P}{CP}\times 100

     =\dfrac{1/36}{1/18}\times 100\Rightarrow 50\%

Hence, The profit is equal to 50%

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