Question

A man bought 2 radio sets for rupee 624. He sold 1 at a lose of 14 percentage and other at a profit of 14 percentage. If the price is same, determine cost price of each.

Answer 1

Answer:312

Step-by-step explanation:

(2 radio=624

1 radio=624/2=312)

1st radio

sp=loss 14%

cp=312

sp=[(100 -loss%) / 100] * CP

=[(100-14)/100]*312=268.32

therefor sp is less than cp,it is loss

loss=sp-cp

=312-268.32

loss=43.68

loss%=(loss*100)/cp

=(43.68*100)/312

=14%

2nd radio

sp=profit 14%

cp=312

sp=[(100 -profit%) / 100] * CP

=[100+14)/100]*312

=355.68

so,therefor cp is less than sp,it is profit

profit=sp-cp

=355.68-312

43.68

profit%=(profit*100)/cp

=(43.68*100)*312

=14%

total cp=312*2=624

total sp=355.68+268.32

=624

hence cp=sp,sp=cp,

no gain no loss