Question

A man bought 2 scooters for Rs 80,000.He sold one of them at a profit of 20%and other at a loss of 10%.If the selling price of each scooter is same.Find the cost price of each scooter. What is the profit or loss percent on the whole transaction?​

pls help me out with this question...

Answer 1

Step-by-step explanation:

let the cost price of the first scooter be X and the second scooter be y.

x+y=80000. eq1

selling price of first scooter =x+20%ofx

=20/100×x+x

=x/5+x

=6x/5

selling price of second scooter =y-10%ofy

=y-10/100×y

=y-y/10

=9y/10

price of both scooter is same .

6x/5=9y/10

60x=45x

4x=3y. eq2

Now you can solve equation 1 an equation 2 by putting the value of equation 2 in equation 1 and hence find the cost price of both the scooters.

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