Question

A man bought 4 horses and 9 cows for 1340. He sells the horses at a profit of 10./. and the cows at a profit of 20./. and his whole gain 188

Answer 1

Step-by-step explanation:

Let the cost price of a horse and a cow be x and y. 4x+9y = 1340 ...(1)and selling price of a horse will be x+(10/100)x =>1.1x. Selling price of a cow will be x+(20/100)x =>1.2x.

4(1.1x)+9(1.2y)-4x-9y =188 =>0.4x+1.8y = 188 => 4x+18y =1880 => 2x+9y=940...(2)

Subtract (2) from (1) we will get 4x+9y-(2x+9y)=1340-940=400 =>2x=400=> x=200 ruppees. Substitute x =>200 in equation (1) => 4(200)+9y=1340=>9y=1340-

900=540 =>y=540/9 = 60 ruppees. Hence the cost prices of horse and cow are 200 ruppees and 60 ruppees. Hope it helps you.