Question

A man bought 4 horses and 9 cows for rs 1340.He sells the horses at a profit of 10% and cows at profit of 20% and his whole gain is Rs188.What price did he pay for horse?

Answer 1

A horse price = 200rupees
A cow price =60 rupees

Answer 2

ANSWER

let us assume that c.p of the horse = x

let us assume that c.p of the horse = y

As given

A man bought 4 horses and 9 cows for rs 1340.

Than the equation

4x + 9y =  1340

As given

He sells the horses at a profit of 10% and cows at profit of 20% and his whole gain is Rs188

10 % written in the decimal form

$=\frac{10}{100}$

= 0.01

20 % written in the decimal form

$=\frac{20}{100}$

= 0.20

than the equation

0.01 ×4x + 0.20× 9y = 188

simplify the equation

4x + 18y = 1880

the two equation becomes

4x + 9y =  1340 and 4x + 18y = 1880

subtracting   4x + 9y =  1340 from 4x + 18y = 1880

9y = 1880 - 1340

9y = 540

y =60

put in 4x + 9y =  1340

4x + 540 = 1340

4x = 1340 - 540

$x = \frac{800}{4}$

x =200

He pay for each horse be Rs 200.

He pay for each cows Rs 60

Hence proved