Question

a man bought 550 oranges at 60 paisa each and 240 oranges at 50 Paisa each if he sold them at the rate of 10 rupees 9 what was his profit percent​

Answer 1

Answer:

58%

Step-by-step explanation:

Cost of first type orange = Rs 0.6

cost 550 oranges of first type orange = 550*0.6 =Rs 330

Cost of second type orange = Rs 0.5

cost 240 oranges of second type orange = 240*0.5 =Rs 120

Total number of orange =550+240 =790

Cost of 1 set (10 Nos) of orange = Rs 9

Number of set of 10 orange =79010 =7979010 =79

cost of 79 set orange =79*9 =711

Therefore he has profit:

Profit percentage =

$\frac{selling \: price \: - \: cost \: price}{cost \: price} \times 100$

$= ( \frac{711 - (330 - 120)}{450} ) \times 100$

= 58%

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