a man bought 63 shirts and sold 4/9 th of them at a profit of 15% above the CP . 1/7 th at a profit at 50% and the remainder at a loss of 25% how much did he pay for the shirts his gain was rupees 1232 on the whole transaction
Answers
Answer:
35280
Step-by-step explanation:
Total shirts brought by man= 63
He sold= 4/9 of them= 4/9*63
= 28 shirts
Total profit on selling 28 shirts= 15%
He sold= 1/7 of them= 1/7*63
= 9 shirts
Total profit on selling 9 shirts= 50%
Total shirts sold= 28+9= 37 shirts
Remaining shirts= 63-37= 26 shirts
Loss on 26 shirts= 25%
Let cost= x
Therefore 15% profit= x*15/100= 15x/100
Therefore cost of 1 shirt having 15% profit= x+ 15x/100
= 115x/100
Therefore selling price of 28 shirts= 28*115x/100= 161x/5
Therefore sp for 28 shirts on 15% profit= 161x/5
50% profit= x*50/100= x/2
1 shirt sp profit= x+x/2= 3x/2
Therefore 9 shirts= 9*3x/2= 27x/2
Loss on shirt= x*25/100= x/4
Sp for 1 shirt= x-x/4
= 3x/4
Therefore 26 shirts= 3x/4*26= 39x/2
Therefore profit= 161x/5+ 27x/2+ 39x/2 - 63x= 1232
= 322x/10 + 135x/10 + 195x/10 - 630x/10= 12320
Therefore profit; 22x=12320
Therefore x= 12320/22
= 560
Thus, 1 shirt cp= 560
Therefore 63 shirts= 560*63
= 35280
Thus, the cost price of all shirts= 35280
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