Question

A man bought a camel and carriage for rs 5000 he sell the camel at a gain of 20% and the carriage at a loss of 10% if the gain 4% on the whole, then find the cost price of the camel
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Answer 1

Answer:

let the cost price of camel=x

and cost price of carriage=5000-x Rs

ACQ

x*120/100+(5000-x)*80/100=5000*104/100

2x+20000=26000

x=3000Rs

Answer 2

Cost of Camel + Carriage = 5000           ( given)

Let consider the cost of Camel = x

∴ cost of Carriage = ( 5000 - x )

The man sold Camel at 20% gain =( x × $\frac{120}{100}$ )

He sold Carriage at 10% loss= ( 5000 - x ) ×$\frac{90}{100}$

In the transaction total gain was 4% = ( 5000 × $\frac{104}{100}$ )

∴ according the question we can say :-

⇒ ( x × $\frac{120}{100}$ ) +  ( 5000 - x ) ×$\frac{90}{100}$  =  ( 5000 × $\frac{104}{100}$ )

⇒ 120x + 450000 - 90x = 520000

⇒ 120x - 90x = 520000 - 450000

⇒ 30x = 7000

⇒ x = $\frac{70000}{ 30}$ = 2333.33

Hence cost price of the Camel was Rs 2333.33

Ans :- Cost price of the Camel was Rs 2333.33