Question

A man bought a certain number of glass vessels for Rs 600.He broke 2 of them, then he sold each of the rest for Rs10 more than he had given for it, there by gaining Rs 50 on the whole How many glass vessels did he buy?​

Answer 1

Answer:

Step-by-step explanation:

No of vessel he buy=X

Cp=600

Sp=610

Sp-cp=50

610(X-2) - 600X=50

X=127

So, no of vessel= 127

Answer 2

He bought 15 glass vessels.

Step-by-step explanation:

Let man bought the number of glass vessels = x

and the man sold glass vessels = y

then, the cost of glass vessels, y = $\frac{600}{x}$

when he broke 2 of them, then he sold each of the rest for Rs. 10 more than he had given for it, thereby gaining Rs. 50 on the whole.

According to the question,

(x-2) × (y+10) = 600+50   [putting the value of y]

(x-2) × ($\frac{600}{x}$ + 10) = 650

(x-2) $\frac{600}{x}$ + 10 (x-2) = 650

600 - $\frac{1200}{x}$ + 10x - 20 = 650

- $\frac{1200}{x}$ + 10x = 650 - 600 + 20

- $\frac{1200}{x}$ + 10x = 70

- 1200 + 10x²  = 70x

10x² - 70x - 1200 = 0

x² - 7x - 120 = 0

x² - 15x + 8x - 120 = 0

x(x-15) + 8(x-15) = 0

(x-15) (x+8) = 0

(x - 15) = 0 or (x + 8) = 0

x = 15 or x = -8

Since the number of glass vessels can not be negative

Hence x = 15

He bought 15 glass vessels.

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