Question

A man bought a certain number of oranges;
out of which 13 percent were found rotten. He
gave 75% of the remaining in charity and still
has 522 oranges left. Find how many had he
bought ? without the algebric method ​

Answer 1

Step-by-step explanation:

Let no.of oranges bought=100

then percentage of oranges rotten=13%

then remaining oranges=100-13% of 100 i.e.=87

percentage given to charity out of left oranges=75% of 87 i.e.=21.75

by unitary method 100 - 21.75 then if 522 are left then no.of oranges bought=522*100/21.75 i.e.=2400

Answer 2

Answer:

2299 approx

Step-by-step explanation:

So he has 522 oranges left of the remaining then means he has 25% of the remaining

if 25%=500

then 1%=500/25

then 100%=500/25×100=500×4=2000

Now this 2000 oranges are the remaining 100-13%=87% of oranges

so, 87%=2000

then 1%=2000/87

then 100%=2000/87×100=2298.85057=2299 approx